Looking for the most accurate NCERT Class 9 Maths Ganita Manjari Chapter 2 Exercise 2.2 solutions? In this post, we provide step-by-step answers for Exercise 2.2, covering linear and quadratic polynomial values along with real-world algebraic applications.
These solutions are updated for the new 2026-27 NCERT syllabus to help students master equation solving and polynomial evaluations.
Class 9 Maths Ganita Manjari Chapter 2 Exercise 2.2 Solutions
Exercise 2.2 - Question 1
Find the value of the linear polynomial \( 5x - 3 \) if:
(i) When \( x = 0 \):
\( 5(0) - 3 = 0 - 3 = \mathbf{-3} \)
(ii) When \( x = -1 \):
\( 5(-1) - 3 = -5 - 3 = \mathbf{-8} \)
(iii) When \( x = 2 \):
\( 5(2) - 3 = 10 - 3 = \mathbf{7} \)
Exercise 2.2 - Question 2
Find the value of the quadratic polynomial \( 7s^2 - 4s + 6 \) if:
(i) When \( s = 0 \):
\( 7(0)^2 - 4(0) + 6 = 0 - 0 + 6 = \mathbf{6} \)
(ii) When \( s = -3 \):
\( 7(-3)^2 - 4(-3) + 6 = 7(9) + 12 + 6 = 63 + 18 = \mathbf{81} \)
(iii) When \( s = 4 \):
\( 7(4)^2 - 4(4) + 6 = 7(16) - 16 + 6 = 112 - 16 + 6 = \mathbf{102} \)
Exercise 2.2 - Question 3
Solution
Let Salil's present age = \( x \) years.
Mother's present age = \( 3x \) years.
After 5 years:
\( (x + 5) + (3x + 5) = 70 \)
\( 4x + 10 = 70 \)
\( 4x = 60 \)
\( x = 15 \)
Mother's age = 3(15) = 45 years
Exercise 2.2 - Question 4
Solution
Let the integers be \( 2x \) and \( 5x \).
According to the question:
\( 5x - 2x = 63 \)
\( 3x = 63 \)
\( x = 21 \)
Second integer = 5(21) = 105
Exercise 2.2 - Question 5
Solution
Let number of ₹5 coins = \( x \).
Number of ₹2 coins = \( 3x \).
Total Value = \( 5(x) + 2(3x) = 88 \)
\( 5x + 6x = 88 \)
\( 11x = 88 \)
\( x = 8 \)
₹2 coins = 3(8) = 24
Exercise 2.2 - Question 6
Solution
Let the shorter piece = \( x \) feet.
Longer piece = \( 4x \) feet.
\( x + 4x = 300 \)
\( 5x = 300 \)
\( x = 60 \)
Longer piece = 4(60) = 240 feet
Exercise 2.2 - Question 7
Solution
Let width = \( x \) cm.
Then, Length = \( 2x + 3 \) cm.
Perimeter = \( 2(Length + Width) \)
\( 24 = 2[(2x + 3) + x] \)
\( 12 = 3x + 3 \)
\( 9 = 3x \)
\( x = 3 \)
Length = 2(3) + 3 = 9 cm
Frequently Asked Questions (FAQs)
1. What is the value of a polynomial at a given point?
The value of a polynomial \( p(x) \) at \( x = a \) is obtained by substituting 'a' in place of 'x' throughout the expression and simplifying it.
2. How do you find the zero of a linear polynomial?
To find the zero of a linear polynomial, set the expression equal to zero (\( p(x) = 0 \)) and solve for the variable \( x \).
3. Are Ganita Manjari Class 9 solutions updated for 2026-27?
Yes, these solutions are strictly based on the latest NCERT Ganita Manjari textbook released for the 2026-27 academic session.
4. Can a zero of a polynomial be 0 itself?
Yes, if substituting \( x = 0 \) makes the entire polynomial value 0, then 0 is a zero of that polynomial.
5. How many zeros can a quadratic polynomial have?
A quadratic polynomial (degree 2) can have at most two zeros.
6. What are real-world applications of finding polynomial zeros?
It is used to solve age problems, calculate dimensions of shapes (like rectangles), and determine unknown quantities in finance, as seen in Exercise 2.2 word problems.
7. Is every real number a zero of a zero polynomial?
Yes, for a zero polynomial \( p(x) = 0 \), every real number substituted for \( x \) will result in 0.
8. Where can I find the next exercise solutions?
You can find the Exercise 2.3 solutions and chapter notes by clicking the navigation links at the bottom of this post.
Conclusion
We hope these NCERT Class 9 Maths Ganita Manjari Chapter 2 Exercise 2.2 solutions have helped you understand the practical applications of polynomials. From evaluating linear expressions to solving complex age and dimension word problems, these fundamentals are crucial for your exams.
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Last updated according to the latest NCERT Ganita Manjari syllabus.