Ex 7.3 Class 9 Maths Ganita Manjari Solutions | Sid Classes

Class 9 Maths Ganita Manjari Ex 7.3 solutions on probability of events with worked examples, step by step. Sid Classes.

Welcome to Sid Classes, your trusted destination for comprehensive academic resources! In this detailed study guide, we present complete solutions for the NCERT Class 9 Maths Ganita Manjari Chapter 7 Exercise 7.3. Designed to reflect how top-scoring students write their solutions and reasoning in school examinations, this walkthrough makes sample spaces, compound experiments, and event subsets entirely clear.

🔑 Key Concepts Used in this Exercise:

  • Sample Space (\(S\)): The set of all possible outcomes of a random experiment.
  • Compound Experiments: Experiments formed by combining two or more simple experiments (e.g., rolling a die and tossing a coin). Their total outcomes can be found using the fundamental counting principle (\(m \times n\)).
  • Event: A subset of the sample space representing specific outcomes of interest.

NCERT Class 9 Maths Ganita Manjari Chapter 7 Exercise 7.3 Solutions

Question 1

When a single 6-sided die is rolled, what is the total number of possible outcomes in the sample space?

Solution:

When a single 6-sided die is rolled, each face numbered \(1, 2, 3, 4, 5,\) and \(6\) has an equal chance of appearing.
Sample space \(S = \{1, 2, 3, 4, 5, 6\}\).

Answer: The total number of possible outcomes is \(\mathbf{6}\).

Question 2

For the following experiments write down the sample space S.
(i) Rolling a die and tossing a coin together.
(ii) Choosing a random integer between \(-5\) and \(+5$.
(iii) A box containing 5 green and 7 red balls. One ball is drawn at random.

Solution:

(i) Rolling a die and tossing a coin together:
A die has \(6\) outcomes \(\{1, 2, 3, 4, 5, 6\}\) and a coin has \(2\) outcomes \(\{H, T\}\).
\(S = \{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)\}\) (Total \(12\) outcomes).

(ii) Choosing a random integer between \(-5\) and \(+5\):
\(S = \{-4, -3, -2, -1, 0, 1, 2, 3, 4\}\).

(iii) A box containing 5 green and 7 red balls. One ball is drawn at random:
Considering individual distinguishable balls: \(S = \{G_1, G_2, G_3, G_4, G_5, R_1, R_2, R_3, R_4, R_5, R_6, R_7\}\) (Total \(12\) outcomes), or represented by color types \(\{ \text{Green}, \text{Red} \}\).

Question 3

In a village fair, there are 3 popular snacks available: Samosa, Pakora, and Bhaji. For drinks, villagers can choose either Chai or Lassi.
(i) List the sample space of all possible snack and drink combinations a person could choose at the fair.
(ii) List the event ‘Selecting Samosa as a snack.’

Solution:

(i) Sample space of all possible snack and drink combinations:
\(S = \{(\text{Samosa}, \text{Chai}), (\text{Samosa}, \text{Lassi}), (\text{Pakora}, \text{Chai}), (\text{Pakora}, \text{Lassi}), (\text{Bhaji}, \text{Chai}), (\text{Bhaji}, \text{Lassi})\}\) (Total \(6\) combinations).

(ii) Event ‘Selecting Samosa as a snack’:
Event \(= \{(\text{Samosa}, \text{Chai}), (\text{Samosa}, \text{Lassi})\}\).


Frequently Asked Questions (FAQs)

Q1: What is a sample space in probability?
A: A sample space is the complete set of all possible distinct outcomes of a random experiment, usually denoted by the letter \(S\).

Q2: How do you find the total number of outcomes in a compound experiment?
A: By using the multiplication rule (fundamental counting principle): if one experiment has \(m\) outcomes and another has \(n\) outcomes, their combination has \(m \times n\) outcomes.


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