Exercise 1.2 Class 9 Maths Solutions | Ganita Manjari

Get step-by-step Exercise 1.2 Class 9 Maths Solutions of Ganita Manjari with easy explanations for CBSE students.

Welcome to Sid Classes, your trusted destination for comprehensive academic resources! In this detailed study guide, we present complete, step-by-step solutions for the NCERT Class 9 Maths Ganita Manjari Chapter 1 Exercise 1.2. Designed to reflect how top-scoring students write their answers in school examinations, this walkthrough makes coordinate geometry, Cartesian plotting, and spatial reasoning entirely clear.

🔑 Key Concepts Used in this Exercise:

  • Cartesian Coordinates: Representing real-world layouts, rooms, and furniture positions using \((x, y)\) coordinate pairs on a graph sheet.
  • Distance Formula & Dimensions: Determining lengths, widths, and structural placements by calculating coordinate differences along the axes.
  • Geometric Shapes on Planes: Identifying squares, rectangles, and trapeziums based on coordinate points and parallel properties.

NCERT Class 9 Maths Ganita Manjari Chapter 1 Exercise 1.2 Solutions

Question 1

Place Reiaan’s rectangular study table with three of its feet at the points (8, 9), (11, 9) and (11, 7).

Solution:

(i) Where will the fourth foot of the table be?

Given three points are \((8, 9)\), \((11, 9)\), and \((11, 7)\).
Therefore, the fourth foot must lie at \(\mathbf{(8, 7)}\) to complete the rectangular shape.


(ii) Is this a good spot for the table?

Yes, this spot is ideal for a study table because:

  • The table is positioned neatly near the wall.
  • It does not obstruct or block any room doors.


(iii) What is the width of the table? The length? Can you make out the height of the table?

• Width of table: Distance between \((8, 9)\) and \((11, 9)\) \(\implies 11 - 8 = \mathbf{3}\) units.
• Length of table: Distance between \((11, 9)\) and \((11, 7)\) \(\implies 9 - 7 = \mathbf{2}\) units.
• Height of the table: No, the height cannot be determined from a 2D Cartesian coordinate plane since height lies along the vertical z-axis, which is not represented here.

Question 2

If the bathroom door has a hinge at B1 and opens into the bedroom, will it hit the wardrobe? Are there any changes you would suggest if the door is made wider?

Solution:

From Fig. 1.5:
• \(B_1 = (0, 1.5)\)
• \(B_2 = (0, 4)\)

The width of the bathroom door is: \(4 - 1.5 = 2.5\) units.
If the bathroom door opens towards the bedroom with \(B_1\) as the hinge point, the door swings in an arc of radius \(2.5\) units.

The wardrobe starts from coordinates \(W_1 = (3, 0)\) to \(W_4 = (3, 2)\). Since the wardrobe is more than \(2.5\) units away from the hinge point \(B_1\), the door will not touch the wardrobe while opening.

Suggested changes if the door is made wider:
• Shift the wardrobe slightly further away, or
• Design the door to open inward to optimize bedroom space.

Question 3

Look at Reiaan’s bathroom.

Solution:

(i) What are the coordinates of the four corners O, F, R, and P of the bathroom?

• \(O = (0, 0)\)
• \(F = (0, 9)\)
• \(R = (-6, 9)\)
• \(P = (-6, 0)\)


(ii) What is the shape of the showering area SHWR in Reiaan’s bathroom? Write the coordinates of the four corners.

Coordinates from Fig. 1.5:
• \(S = (-6, 5)\)
• \(H = (-3, 5)\)
• \(W = (-2, 9)\)
• \(R = (-6, 9)\)

Since points \(S\) and \(H\) lie on the horizontal line \(y = 5\), and points \(R\) and \(W\) lie on the horizontal line \(y = 9\), side \(SH\) is parallel to side \(RW\). Because one pair of opposite sides is parallel, quadrilateral \(SHWR\) is a trapezium.


(iii) Mark off a 3 ft × 2 ft space for the washbasin and a 2 ft × 3 ft space for the toilet. Write the coordinates of the corners of these spaces.

Washbasin Space (3 ft × 2 ft):
Placed in the lower-left corner of the bathroom with coordinates:
\((-6, 0), (-3, 0), (-3, 2), (-6, 2)\)

Toilet Space (2 ft × 3 ft):
Placed just above the washbasin area with coordinates:
\((-6, 2), (-4, 2), (-4, 5), (-6, 5)\)

Question 4

Other rooms in the house:

Solution:

(i) Reiaan’s room door leads from the dining room which has length 18 ft and width 15 ft. The length of the dining room extends from point P to point A. Sketch the dining room and mark the coordinates of its corners.

PNMA represents the dining room layout.


(ii) Place a rectangular 5 ft × 3 ft dining table precisely in the centre of the dining room. Write down the coordinates of the feet of the table.

Coordinates of the dining table feet are: \(\mathbf{(0.5, -6), (5.5, -6), (5.5, -9), (0.5, -9)}\).


Frequently Asked Questions (FAQs)

Q1: What is Exercise 1.2 Class 9 Maths about?
A: Exercise 1.2 of Class 9 Maths focuses on coordinate geometry and helps students understand plotting points and real-world spatial layouts on the Cartesian plane.

Q2: Are these Exercise 1.2 solutions based on the latest CBSE syllabus?
A: Yes, these solutions are prepared according to the latest CBSE syllabus and NCERT Ganita Manjari guidelines.

Q3: How can I solve coordinate geometry questions easily?
A: Students should practice plotting points regularly and understand the x-axis, y-axis, and coordinate differences clearly.

Q4: Can I use these solutions for exam preparation?
A: Yes, these step-by-step solutions are extremely useful for homework, revision, and CBSE school exam preparation.


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